Electric Heat Strip kW to Amps Calculator
Find the current and heat output of an electric heat kit — including how much less heat a 240 V heater gives on a 208 V supply.
Method reviewed October 26, 2026. Version 1.0.0. How it works
Result
- Current
- 41.7A
- Output at the actual voltage
- 10kW
- Heat output
- 34,121BTU/h
41.7 A and 34,121 BTU/h (10 kW) at 240 V.
- For wire and breaker sizing use the minimum circuit ampacity and maximum overcurrent protection printed on the equipment nameplate, and the electrical code that applies — not this current.
- Share of rated output
- 100%
Show the working
- A resistance heater’s power varies with voltage squared (P = V² ÷ R)10 × (240 ÷ 240)² = 10 kW
- Current = W ÷ V10,000 ÷ 240 = 41.67 A
- Heat = W × 3.41210,000 × 3.412 = 34,121 BTU/h
Amps from kilowatts
For a single-phase resistance heater, current = watts ÷ volts: a 10 kW heater at 240 V draws about 41.7 A. For a balanced three-phase heater, current = watts ÷ (1.732 × line-to-line volts). Every watt becomes heat: 1 kW = 3,412 BTU/h.
Why 208 V gives less heat
A heating element is a fixed resistance, so its power follows P = V² ÷ R. Run a 240 V element on 208 V and it delivers (208 ÷ 240)² = 75 % of its rating: a 10 kW strip gives about 7.5 kW (25,600 BTU/h) and draws about 36 A.
That matters when sizing backup heat for a heat pump in a building with a 208 V supply.
Worked example
These are the example values the calculator opens with, and the result the engine calculates for them.
Inputs
- Rated heater output
- 10 kW
- Rated voltage
- 240 V
- Actual supply voltage
- 240 V
- Supply
- Single-phase
Result
- Current
- 41.7 A
- Output at the actual voltage
- 10 kW
- Heat output
- 34,121 BTU/h
- Share of rated output
- 100 %
41.7 A and 34,121 BTU/h (10 kW) at 240 V.
Assumptions
- The heating element is a constant resistance, so output scales with the square of the voltage.
- Three-phase heaters are balanced.
Limitations
- Element resistance changes slightly with temperature; nameplate values govern.
- Does not size wire or overcurrent protection.
Frequently asked questions
How many amps is a 5 kW heat strip?
About 20.8 A at 240 V, or about 18 A (with 3.75 kW output) if the 240 V strip runs on 208 V.
Can I use this to size the breaker?
No. Use the minimum circuit ampacity and maximum overcurrent protection on the equipment nameplate and the electrical code that applies.
Does the blower motor add to the current?
Yes. This tool gives the heater only; the air handler’s nameplate lists the total.
Sources
- University Physics Volume 2, §9.4 Ohm’s Law — OpenStax, Rice University (CC BY 4.0). V = IR; electrical power P = IV.
- NIST Guide to the SI (SP 811), Appendix B.9 — conversion factors — National Institute of Standards and Technology. 1 ton of refrigeration = 12,000 BTU/h; 1 BTU/h = 0.2930711 W; 1 atm = 101.325 kPa.
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